4[11a+7a-5(3a-1)]=3a+2

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Solution for 4[11a+7a-5(3a-1)]=3a+2 equation:


Simplifying
4[11a + 7a + -5(3a + -1)] = 3a + 2

Reorder the terms:
4[11a + 7a + -5(-1 + 3a)] = 3a + 2
4[11a + 7a + (-1 * -5 + 3a * -5)] = 3a + 2
4[11a + 7a + (5 + -15a)] = 3a + 2

Reorder the terms:
4[5 + 11a + 7a + -15a] = 3a + 2

Combine like terms: 11a + 7a = 18a
4[5 + 18a + -15a] = 3a + 2

Combine like terms: 18a + -15a = 3a
4[5 + 3a] = 3a + 2
[5 * 4 + 3a * 4] = 3a + 2
[20 + 12a] = 3a + 2

Reorder the terms:
20 + 12a = 2 + 3a

Solving
20 + 12a = 2 + 3a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3a' to each side of the equation.
20 + 12a + -3a = 2 + 3a + -3a

Combine like terms: 12a + -3a = 9a
20 + 9a = 2 + 3a + -3a

Combine like terms: 3a + -3a = 0
20 + 9a = 2 + 0
20 + 9a = 2

Add '-20' to each side of the equation.
20 + -20 + 9a = 2 + -20

Combine like terms: 20 + -20 = 0
0 + 9a = 2 + -20
9a = 2 + -20

Combine like terms: 2 + -20 = -18
9a = -18

Divide each side by '9'.
a = -2

Simplifying
a = -2

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